Follow along with the video below to see how to install our site as a web app on your home screen.
Note: This feature may not be available in some browsers.
yah that makes sence, but i think that is more of an academic argument than actual performance results
conventional drive train format ..
engine fixed to primary
secondary fixed to all downstream components and track
belt is the dynamic tie between
the power ultimately is released to make the track spin, there is inherit drag and loss of efficiency with every transfer point.
primary to belt
secondary to jackshaft belt slip
chain / belt power transfer from jack shaft to drive shaft
there is room for improvement and increased efficiency within all those power transfer points on a sled..
the key component of my argument is the power transfer from the track to the ground.
snow pack composition, and all natural sciences that go into the creation of a snowflake and the matrix that forms them together..
we all know track speed is not the same as ground speed
track speed is what all the components efficiency produce, ground speed is the end result.
if we were concerned with rotating mass we would all be running 121s with .375 or shorter lug high ,, this would produce the highest track speed.
low inherit rotating mass and * key attribute* low resistance feedback from the snow to the track.
but we run 2 inch , 2.25 2.5 and now 3 inch tracks ,, 144 152 164 174 lengths
the longer the track , the deeper the lug the more resistance feedback is translated from the track to the snow.. pushing us forward, faster, and higher
lets for sake of argument there is 5 lbs of inherit drag or efficiency loss from the secondary to driveshaft drivers ..you can measure that with the track off and turn the secondary by hand and see how hard it is for you to make the drivers turn by rotating the secondary by hand.
now put the track on the drivers and get it all ready to run..
then turn the secondary by hand with the sled in 2 feet of fresh powder and the track is a 174 x3 16 wide .. how easy will that bee to turn the secondary by hand?
ok that is resistance feedback. and i would take a stab and say its 50 lbs ,,
ok before the track was on there was 5 lb resistance ,, now there is 55 lb resistance..
lets say a belt drive is twice as efficient as a chain .. brings that down to 2.5.. track still produces the same amount of feedback
so
chain drive 55 lb resistance
belt drive 52.5 lb resistance
kind of spending a pound to save a penny
Most current systems are pushing 40-50 pounds crankshaft to track.
Just a thought here, but I was under the impression that a Diamond Lite Drive, driveshaft, brake, and secondary was in the neighborhood of 27lbs. I might be wrong but that number rings a bell.
rotating mass could be an exponential relationship, not sure if it is but if it is then that changes things big time.
loud handle, what you are designing sounds a lot like a viscous coupling differential.
interesting concept , removing the jack shaft all together
oh and im sure in the most extreme of performance applications where .001 thousands of a second determine a Win or a loss such as in drag racing. i agree all out performance every bit of weight loss to the drive system would be best.
same could be said for the space shuttle . all out spare no expense performance such as these extreme engineering examples.. i totally agree.
and thank you for your input